01-19-2011, 07:25 PM
(This post was last modified: 01-20-2011, 11:13 AM by TheouAegis.)
I'll toy with that tonight (haven't slept yet, shit i'm screwed tonight).
The thing I'm looking for, the whole point of this post really, is how to get Aop(K)=Bop(3b/2)-Cop(d/3) where Bop() and Cop() may be the same operation or different as long as they're the same for every set and still yield Aop(K) so that Aop(Kmid)/Aop(Kmax)=Kmid/Kmax; in other words, what I want isn't the operation to reduce K to the set {1,...,50} but rather to find the operation(s) that I can make to 3b/2 and d/3 individually to yield that result.
Bedtime. 4 hours ain't enough.
Edit: Modulo wouldn't work anyway, I just remembered. 20 mod 50 = 70 mod 50 and if 70 was the largest value, then 20/70 != 70/70 and wouldn't work, I didn't really need to add that last bit of explanation because once I pointed out 20-70 it was all over. I will add though that in my operation I'm striving for, 20 could equal 30, for example, but ideally no more than a differential of 10, ideally 8 or less.
The thing I'm looking for, the whole point of this post really, is how to get Aop(K)=Bop(3b/2)-Cop(d/3) where Bop() and Cop() may be the same operation or different as long as they're the same for every set and still yield Aop(K) so that Aop(Kmid)/Aop(Kmax)=Kmid/Kmax; in other words, what I want isn't the operation to reduce K to the set {1,...,50} but rather to find the operation(s) that I can make to 3b/2 and d/3 individually to yield that result.
Bedtime. 4 hours ain't enough.
Edit: Modulo wouldn't work anyway, I just remembered. 20 mod 50 = 70 mod 50 and if 70 was the largest value, then 20/70 != 70/70 and wouldn't work, I didn't really need to add that last bit of explanation because once I pointed out 20-70 it was all over. I will add though that in my operation I'm striving for, 20 could equal 30, for example, but ideally no more than a differential of 10, ideally 8 or less.